Answer:
The head difference across the soil specimen is 39.29 cm and the discharge velocity is 0.02 cm/s
Explanation:
The head difference across the soil specimen is:
[tex]k=\frac{QL}{Aht}[/tex]
Where
k = hydraulic conductivity = 0.014 cm/s
Q = volume of water collected = 150 cm³/min = 2.5cm³/s
L = length of the soil specimen = 275 mm = 27.5 cm
A = area = 125 cm²
Replacing:
[tex]0.014=\frac{2.5*27.5}{125*h*1} \\h=39.29cm[/tex]
The hydraulic gradient is:
[tex]i=\frac{h}{L} =\frac{39.29}{27.5} =1.43[/tex]
The discharge velocity is:
v = k*i = 0.014 * 1.43 = 0.02 cm/s
