Answer:
AG = 4
AH = 21
EC = 12
CH = 5
HE = 7
Step-by-step explanation:
We were given that the diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.
HE is the radius of circle E whose diameter is 14cm.
This means that:
[tex]HE = \frac{1}{2} \times 14 = 7cm[/tex]
CE is the radius of circle C whose diameter is 24cm.
[tex]CE = \frac{1}{2} \times 24 = 12cm[/tex]
Also CE=CH +HE
This means 12=CH+7cm
CH=12-7
CH=5cm.
AC is the radius of circle A, whose diameter is 32cm
[tex]AC = \frac{1}{2} \times 32 = 16cm[/tex]
AG=AC-GC
AC=16-12=4cm
AH=AC+CH
AH=16+5
AH=21cm.
EC=HE+CH
EC=7+5
EC=12cm