Respuesta :
Answer:
Explanation:
If H be the heat flowing in time t through an area of A having thickness d
H = k A x ( θ₂ - θ₁ ) t / d , k is thermal conductivity , ( θ₂ - θ₁ ) is temperature difference of walls
putting the given values
= (1.12 x 2.8x 5 x 9 x 16.7 x 60 x 60) / .08
= 1.06 x 10⁸ J .
The heat flows through the wall in a 16.7 h period when the average inside and outside temperatures should be 1.06 x 10⁸ J.
Calculation of the heat flows:
Here we assume that
H be the heat flowing in time t via an area of A having thickness d
So,
H = k A x ( θ₂ - θ₁ ) t / d ,
Here, k is thermal conductivity ,
( θ₂ - θ₁ ) is temperature difference of walls
So,
= (1.12 x 2.8x 5 x 9 x 16.7 x 60 x 60) / .08
= 1.06 x 10⁸ J
hence, The heat flows through the wall in a 16.7 h period when the average inside and outside temperatures should be 1.06 x 10⁸ J.
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