Answer:
18.7842493212 W
Explanation:
T = Tension = 1871 N
[tex]\mu[/tex] = Linear density = 3.9 g/m
y = Amplitude = 3.1 mm
[tex]\omega[/tex] = Angular frequency = 1203 rad/s
Average rate of energy transfer is given by
[tex]P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W[/tex]
The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W
