Suppose you made the intestinal sac too small, and at the end of experiment you could collect only 100 microliters of solution instead of 200 microliters for analysis. You perform the DNS reaction with 100 ul of the recovered solution and 100 ul of water (to bring volume up to 200 ul). How that would affect the concentration of glucose you determined from the standard curve?

Normal Experiment
200 ul solution
200 ul of DNS
400 ul of H2O

A)Half the true concentration
B)Twice the true concentration
C)Equal to the true concentration

According to what was expressed in the problem, the experiment has to be done with 200 ul of solution, with 200 ul of DNS and finally with 400 ul of H2O. The expression in the problem says that 100 ul of solution is recovered and 100 ul of DNS are added, and 200 ul of H2O are added, but it is said that only half of the solution was added (100 ul of H2O), leading to a increase in glucose concentration.

tallinn tallinn · Answer 2 · 2022-03-31T20:27:42+02:00

When The concentration of glucose you determined from the standard curve is Twice the true concentration So Correct Option is B.

What is a DNS reaction?

According to what was they are expressed in the problem When the experiment has to be done with 200 ul of the solution, with 200 ul of DNS, and also finally with 400 ul of H2O. When The expression in the problem says that 100 ul of the solution is recovered and 100 ul of DNS are added, and also 200 ul of H2O are added, but it is said that only half of the solution was added (100 ul of H2O), leading to an increase in glucose concentration.

Therefore, the Correct option is 'B'. Twice the true concentration

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