Answer: 118.5 grams
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml = 500 ml
[tex]1.50=\frac{moles\times 1000}{500ml}[/tex]
moles = 0.75
moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}[/tex]
0.75 =[tex]\frac{\text {given mass}}{158g/mol}[/tex]
mass of [tex]KMnO_4[/tex] = 118.5 grams
Thus mass of [tex]KMnO_4[/tex] needed to prepare 500 mL of this solution iis 118.5 grams
