Company B; the ratios of cost to weight are equivalent.
Step-by-step explanation:
Step 1:
In the equation, [tex]y=kx[/tex] k is the constant of proportionality.
If the values are in accordance with [tex]y=kx[/tex], the values of k will be constant for all the values.
So we determine the values of k for both the companies and see which has a constant k.
If [tex]y=kx, k = \frac{y}{x}[/tex]. In these tables, y is the total cost and x is the weight in lbs.
Step 2:
For company A,
when [tex]y=10.55, x=1, k = \frac{10.55}{1} = 10.55,[/tex]
when [tex]y=10.85, x=2, k = \frac{10.85}{2} = 5.425,[/tex]
when [tex]y=11.15, x=3, k = \frac{11.15}{3} = 3.71666.[/tex]
For company B,
when [tex]y=2.75, x=1, k = \frac2.75}{1} = 2.75,[/tex]
when [tex]y=5.50, x=2, k = \frac{5.50}{2} = 2.75,[/tex]
when [tex]y=8.25, x=3, k = \frac{8.25}{3} = 2.75.[/tex]
So company B has a constant value of [tex]k=2.75[/tex].
