Answer:
13.12°
Explanation:
Parameters given:
Magnetic field strength, B = 0.350 T
Current in the wire, I = 3.5 A
Force per unit length, F/L = 0.278 N/m
The force on a wire due to the presence of a magnetic field is given as:
F = I*L*B*sinФ
where Ф = angle between the magnetic field and current
The force per unit length, F/L, will be:
F/L = I*B*sinФ
0.278 = 3.5 * 0.35 * sinФ
=> sinФ = [tex]\frac{0.278}{3.5 * 0.35}[/tex]
sinФ = 0.227
Ф = [tex]sin^{-1}(0.227)[/tex]
Ф = 13.12°
The angle between the magnetic field and the current is 13.12°.
