Answer:
The magnitude of the change in linear momentum of the ball is 6 kg-m/s.
Explanation:
Given that,
Mass of the ball, m = 1 kg
Initial sped of the ball, u = 3 m/s
It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s
The magnitude of the change in linear momentum of the ball is given by :
[tex]p=m(v-u)\\\\p=1\ kg\times (-3-3)\\\\p=-6\ kg-m/s[/tex]
So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.
