Ok.. So I see a recurring theme that we do not cover in any of my lecture notes. This is a trig function. COS²θ - SIN²θ = 1 I have to demonstrate why COS²θ MINUS SIN²θ = 1... But every transformation I make leads me to believe that this can never be true. Help?

Respuesta :

Answer:

Because the actual identity says  [tex]\sin ^{2}\theta +\cos ^{2}\theta = 1[/tex]

Step-by-step explanation:

The trigonometric ratios [tex]\sin \theta[/tex] and [tex]\cos\theta[/tex] have a maximum value of 1. And hence [tex]\cos^{2}\theta[/tex] and [tex]\sin^{2}\theta[/tex] will have values between 0 and 1 as they are squares and will be always positive.

But if we look at the equation [tex]\cos^{2}\theta-\sin^{2}\theta=1[/tex] shows that [tex]\cos^{2}\theta[/tex] will be more than 1. Hence it is an incorrect equation.

The correct relation between [tex]\cos^{2}\theta[/tex] and [tex]\sin^{2}\theta[/tex] is [tex]\sin ^{2}\theta +\cos ^{2}\theta = 1[/tex].