Answer:
The necessary information is if the forces acting on the block are in equilibrium
The coefficient of friction is 0.577
Explanation:
Where the forces acting on the object are in equilibrium, we have;
At constant velocity, the net force acting on the particle = 0
However, the frictional force is then given as
F = mg sinθ
Where:
m = Mass of the block
g = Acceleration due to gravity and
θ = Angle of inclination of the slope
F = 5×9.81×sin 30 = 24.525 N
Therefore, the coefficient of friction is given as
24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479
μ × 42.479 N= 24.525 N
∴ μ = 24.525 N ÷ 42.479 N = 0.577
Answer:
We only need the angle of inclination.
The coefficient of friction is 0.58
Explanation:
Check attachment for diagram
For a book placed on an inclined plane, the force acting on the object causing it to slide downwards is the moving Force (Fm).
Fm = Wsin(theta) = mgsin(theta)
The force opposing the moving force is the frictional force Ff
Ff = nR where
n is the coefficient of friction
R is the normal reaction = mgcos(theta)
For the body to have a constant velocity (not accelerate), then Fm =Ff and W = R
n = Ff/R
n = Fm/R
n = Wsintheta/Wcostheta
n = sintheta/costheta
n = tan(theta)
Given theta = 30°
n = tan 30°
n = 0.58
the coefficient of friction between the block and the plane is 0.58
The calculation shows that the only information we need to get the coefficient of friction is the angle is inclination
