Answer:
1.512 m/s
Explanation:
M₁ = 10.5
M₂ = 61.5kg
v₁ = 8.85m/s
v₂ = ?
This question involves conservation of momentum and law of conservation of momentum states that, the total momentum of a system does not change before and after impact and it's always constant.
Momentum = mass * velocity = M*V
total momentum of the system before caught the ball = total momentum after he caught the ball.
M₁V₁ = M₂V₂
10.5 * 8.85 = 61.5 * V₂
V₂ = 92.925 / 61.5
V₂ = 1.5109m/s ≈ 1.512m/s
Answer:
The recoil velocity is 1.29 m/s
Explanation:
In a collision, the momentum is conserved:
m₁v₁ + m₂v₂ = V(m₁ + m₂)
Where
m₁ = mass of ball = 10.5 kg
m₂ = mass of performer = 61.5 kg
v₁ = velocity of the ball = 8.85 m/s
v₂ = velocity of performer = 0
V = velocity after the collision = ?
Clearing V:
[tex]V=\frac{m_{1}v_{1}+m_{2}m_{2}}{m_{1}+m_{2} } =\frac{(10.5*8.85)+(61.5*0)}{10.5+61.5} =1.29m/s[/tex]
