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An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple harmonic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.100.10 m

Respuesta :

Answer:

Acceleration will be equal to [tex]2m/sec^2[/tex]      

Explanation:

We have given mass of the object m = 0.4 kg

Spring constant k = 8 N/m

Maximum displacement of the spring is given x = 0.1 m

From newton's law force is equal to [tex]F=ma[/tex].....eqn 1

By hook's law spring force is equal to [tex]F=kx[/tex] .....eqn 2

From equation 1 and equation 2

[tex]ma=kx[/tex]

[tex]0.4\times a=8\times 0.1[/tex]

[tex]a=2m/sec^2[/tex]

So acceleration will be equal to [tex]2m/sec^2[/tex]