What is the final pressure when 100.0mL of a gas at 5.00 atm is compressed to 25.0mL at constant temperature?
(help! timed Test)
A.) 1.25 atm
B.) 500 atm
C.) 10.0 atm
D.) 20.0 atm

Respuesta :

Answer:

D) 20.0 atm

Explanation:

To solve this problem, we can apply Boyle's law, which states that:

"For a constant mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to the volume of the gas".

Mathematically:

[tex]pV=const[/tex]

where

p is the gas pressure

V is the volume of the gas

The equation can also be rewritten as

[tex]p_1 V_1 = p_2 V_2[/tex]

where in this problem:

[tex]p_1=5.00 atm[/tex] is the initial pressure of the gas

[tex]V_1=100.0 mL[/tex] is the initial volume of the gas

[tex]V_2=25.0 mL[/tex] is the final volume of the gas

Solving for p2, we find the final pressure of the gas:

[tex]p_2 = \frac{p_1 V_1}{V_2}=\frac{(5.00)(100.0)}{25.0}=20.0 atm[/tex]