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A possible reaction for the degradation of the pesticide DDT to a less harmful compound was simulated in the laboratory. The reaction was found to be first-order, with at . What is the half-life for the degradation of DDT in this experiment, in years?

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Answer:

This exercise is incomplete, missing the value of k (decay constant), which is equal to 4x10⁻⁸s⁻¹ at 25°C

The answer is 0.549 years

Explanation:

Given:

first order of reaction

k = 4x10⁻⁸s⁻¹

For a first order of reaction, the half-life time for the degradation of DDT is equal to:

[tex]t=\frac{0.693}{k} =\frac{0.693}{4x10^{-8} } =17325000s=0.549years[/tex]

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