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A High Dive A 62.3 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 1.14 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Respuesta :

lublana

Answer:

2276.1 N

Explanation:

We are given that

Mass of person,m=62.3  kg

Initial velocity,u=0

Final velocity,v=0

Initial kinetic energy=Final kinetic energy=0

y=3.11 m

d=1.14 m

h=3.11+1.14=4.25 m

Final height, h'=0

Work done=Change in P.E energy

[tex]-Fd=mg(h'-h)=-mg(h-h')[/tex]

[tex]Fd=mg(4.25-0)[/tex]

[tex]F=\frac{62.3\times 9.8\times 4.25}{1.14}[/tex]

[tex]F=2276.1 N[/tex]

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