Answer:
0.157 V
Explanation:
Parameters given:
Number of turns, N = 1207
Diameter of coil = 20 cm = 0.2 m
Radius of coil, r = 0.2/2 = 0.1 m
Magnetic field strength, B = [tex]4.13 * 10^{-5} T[/tex]
Time interval, t = 10 ms = [tex]10 * 10^{-3} = 0.01 s[/tex]
The average EMF induced in a coil due to a magnetic field is given as:
EMF = [tex]\frac{- N * A * B}{t}[/tex]
where A = Area of coil
A = π[tex]r^{2}[/tex]
Therefore, EMF will be:
[tex]EMF = \frac{- 1207 * 3.142 * 0.1^2 * 4.13 * 10^{-5}}{0.01} \\\\\\EMF = -0.157 V\\[/tex]
