Answer:
The correct option is B
Explanation:
In part A pressure is given as [tex]1.01*10^5 N/m[/tex]
In Part B we can calculate the pressure using the formula
[tex]P = \frac{F}{A}[/tex]
Where F is the force which in this case is weight which can be obtained as follow
W = Mg
Substituting 70kg for M and [tex]9.8m/s^2[/tex] for g
[tex]W = 70 *9.8[/tex]
[tex]=686N[/tex]
A is the area with a value [tex]50cm^2 = \frac{50}{10000} = 5.0*10^{-3}m^2[/tex]
So substituting into the above equation
[tex]P = \frac{686}{5.0*10^{-3}}[/tex]
[tex]= 1.37 *10^5 N/m^2[/tex]
for part c
A [tex]= 22*28 cm^2= \frac{22*28}{10000}m^2[/tex]
[tex]=6.16*10^{-2}m^2[/tex]
F [tex]= 2.5 * 9.8[/tex]
[tex]= 24.525N[/tex]
Therefore [tex]P = \frac{24.252}{6.16*10^{-2}}[/tex]
[tex]= 298 N/m^2[/tex]
From this we see that the value of P for part B is the greatest
