A gas has a volume of 1,400 milliliters at a temperature of 20. K and a pressure of 1.0 atm. What will be the new volume when the temperature is changed to 40. K and the pressure is changed to 0.50 atm

Respuesta :

Answer : The new volume of will be, 5600 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1,V_1\text{ and }T_1[/tex] are the initial pressure, volume and temperature of the gas

[tex]P_2,V_2\text{ and }T_2[/tex] are the final pressure, volume and temperature of the gas

We are given:

[tex]P_1=1.0atm\\V_1=1400mL\\T_1=20K\\P_2=0.50atm\\V_2=?\\T_2=40K[/tex]

Now put all the given values in above equation, we get:

[tex]\frac{1.0atm\times 1400mL}{20K}=\frac{0.50atm\times V_2}{40K}[/tex]

[tex]V_2=5600mL[/tex]

Therefore, the new volume of will be, 5600 mL