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You are given a straight piece of conductor that is 5.5 cm long and moves in a region of uniform magnetic field of 1.7 T along the z-direction. If the conductor is oriented along the x-axis and moves in the y-direction with a velocity of 4.0 m/s, find the magnitude of induced voltage that will be produced between the ends of this moving conductor.

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mavila18

Answer:

e=0.374V

Explanation:

the induced voltage is the work done per unit of charge. Hence we have

[tex]\epsilon=\frac{W}{q}=\frac{FL}{q}=\frac{qvBLsin\theta}{q}[/tex]

however, the angle between the piece of conductor and the field is 0°. Hence

[tex]\epsilon=vBL=(4.0\frac{m}{s})(1.7T)(0.055m)=0.374V[/tex]

THE INDUCED VOLTAGE IS 0.374V

hope this helps!!

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