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A large aquarium of height 5 m is filled with fresh water to a depth of D = 2.20 m. One wall of the aquarium consists of thick plastic with horizontal length w = 8.20 m. By how much does the total force on that wall increase if the aquarium is next filled to a depth of D = 4.40 m? (Note: use g = 9.81 m/s2 and rho = 998 kg/m3.)

Respuesta :

Answer:

[tex]P=21538.836\ Pa[/tex]

Explanation:

Given:

Initial depth of water in the aquarium,  [tex]D_i=2.2\ m[/tex]

width of a wall of aquarium, [tex]w=8.2\ m[/tex]

final depth of the water in the aquarium, [tex]D_f=4.4\ m[/tex]

Now the change in pressure on the wall:

[tex]P=\rho.g.(D_f-D_i)[/tex]

[tex]P=998\times 9.81\times (4.4-2.2)[/tex]

[tex]P=21538.836\ Pa[/tex]

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