M is the midpoint of PQ. The diameter of circle O is 15 in. and RM = 3 in.

Answer:
PM=6 inches
PQ=12 inches
Step-by-step explanation:
-The product of the segments of chords that intersect within a circle are always equal.
[tex]RM.MS=PM.MQ[/tex]
Given that PM=MQ and RS=15(MS=15-3=12):
[tex]RM.MS=PM.MQ\\\\12\times 3=PM^2=MQ^2\\\\36=PM^2\\\\PM=MQ=6\ in \\\\PQ=PM+MQ=2\times 6=12\ in[/tex]
Hence, the length PM is 6 inches and PQ is 12 inches