Respuesta :
Answer:
Theoretical yield of [tex]CO_{2}[/tex] is 3.51 g.
Explanation:
Balanced equation: [tex]CH_{4}+2O_{2}\rightarrow CO_{2}+2H_{2}O[/tex]
Molar mass of [tex]CH_{4}[/tex] = 16.04 g/mol
Molar mass of [tex]O_{2}[/tex] = 32.00 g/mol
So, 1.28 g of [tex]CH_{4}[/tex] = [tex]\frac{1.28}{16.04}mol[/tex] of [tex]CH_{4}[/tex] = 0.0798 mol of [tex]CH_{4}[/tex]
10.1 g of [tex]O_{2}[/tex] = [tex]\frac{10.1}{32.00}mol[/tex] of [tex]O_{2}[/tex] = 0.316 mol of [tex]O_{2}[/tex]
According to balanced equation-
1 mol of [tex]CH_{4}[/tex] produces 1 mol of [tex]CO_{2}[/tex]
So, 0.0798 mol of [tex]CH_{4}[/tex] produce 0.0798 mol of [tex]CO_{2}[/tex]
2 moles of [tex]O_{2}[/tex] produce 1 mol of [tex]CO_{2}[/tex]
So, 0.316 mol of [tex]O_{2}[/tex] produce 0.158 mol of [tex]CO_{2}[/tex]
As least number of moles of [tex]CO_{2}[/tex] are produced from [tex]CH_{4}[/tex] therefore [tex]CH_{4}[/tex] is the limiting reagent.
So, theoretical yield of [tex]CO_{2}[/tex] = 0.0798 mol
Molar mass of [tex]CO_{2}[/tex] = 44.01 g/mol
So, theoretical yield of [tex]CO_{2}[/tex] = [tex](44.01\times 0.0798)g=3.51g[/tex]
