The distance between the point (-2, -1) and point G (3, -1) is 5 units the point B is the correct choice, the option (B) is correct.
What is an ordered double?
It is defined as a representation of coordinates in a two-dimensional coordinate plane. It has a list of two elements in it, such as (x, y).
[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]
It is given that:
Point G is the point (3,-1)
To find the point such that the distance between the point and point G is 5 units we can use the distance formula:
As we know, the distance formula can be defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.
The distance formula can be given as:
[tex]\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
A.point A:
A(-1, -1)
[tex]\rm AG=\sqrt{(-1-3)^2+(-1+1)^2}[/tex]
AG = 4 units
B.point B:
B(-2, -1)
[tex]\rm BG=\sqrt{(-2-3)^2+(-1+1)^2}[/tex]
BG = 5 units
C.point C:
C(-2, 4)
[tex]\rm CG=\sqrt{(-2-3)^2+(4+1)^2}[/tex]
CG = √50
CG = 5√2
D.point D:
D(3, 3)
[tex]\rm DG=\sqrt{(3-3)^2+(3+1)^2}[/tex]
DG = 4 units
Thus, the distance between the point (-2, -1) and point G (3, -1) is 5 units the point B is the correct choice, the option (B) is correct.
Learn more about the order double here:
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