Suppose a uniform random variable can be used to describe the outcome of an experiment with the outcomes ranging from 50 to 80. What is the probability that this experiment results in an outcome less than 60​?

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Answer:

The correct answer is [tex]\frac{1}{3}[/tex] = 0.33.

Step-by-step explanation:

A uniform random variable is used to describe the outcome of an experiment with the parameters being 50 and 80.

Probability density function = f(x) = [tex]\left \{ {{\frac{1}{b-a} , a<x<b} \atop {0 ,otherwise}} \right.[/tex]

Here a = 50 and b = 80.

We need to find the value of probability of this given experiment in an outcome less than 60.

∴ P(X<60) = [tex]\frac{60-50}{80-50} = \frac{10}{30} = \frac{1}{3}[/tex] = 0.33.

Thus the required probability is given by 0.33.

Probability [numbers less than 60 between 50 to 80] is 1/3

Given that;

Total numbers between 50 to 80 = 80 - 50 = 30

Total numbers less than 60 between 50 to 80 = 60 - 50 = 10

Find:

Probability [numbers less than 60 between 50 to 80]

Computation:

Probability [numbers less than 60 between 50 to 80] = Total numbers less than 60 between 50 to 80 / Total numbers between 50 to 80

Probability [numbers less than 60 between 50 to 80] = 10 / 30

Probability [numbers less than 60 between 50 to 80] = 1/3

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