Answer:
8427375 N
Explanation:
From newton's equation of motion,
F = ma................. Equation 1
Where F = average force exerted on the meteorite by the car, m = mass of the meteorite, a = acceleration.
We can find the value of acceleration from newton's equation of motion
using,
v² = u²+2as.................. Equation 2
Where v = final velocity, u = initial velocity, a = acceleration, s = distance.
Make a the subject of the equation
a = (v²-u²)/2s............... Equation 3
Note: When the meteorite struck the car, it was brought to rest
Given: u = 550 m/s, v = 0 m/s ( brought to rest), s = 22 cm = 0.22 m
Substitute into equation 3
a = (0²-550²)/(2×0.22)
a = -302500/0.44
a = -687500 m/s²
Also given: m = 27 pound = (27×0.454) = 12.258 kg
Substitute into equation 1
F = 12.258(-687500)
F = -8427375 N
Note: The negative sign tells that the force act in opposite direction to the motion of the meteorite
Answer:
The average force exerted on the meteorite by the car is 8.435x10⁶N
Explanation:
Given:
m = 27 lb = 12.27 kg
D = 22 cm = 0.22 m
v1 = 550 m/s
The acceleration of the meteorite is:
[tex]v_{2} ^{2} =v_{1} ^{2}+2aD\\0=550^{2} +2a(0.22)\\a=-\frac{550^{2} }{2*0.22} =-687500m/s^{2}[/tex]
Negative sign indicates opposite to the initial velocity. The average force is equal to:
Magnitude of a = 687500 m/s²
F = m*a = 12.27 * 687500 = 8.435x10⁶N
