Answer:
87.08% percentage of families spend more than $4000 annually on food and drink
Step-by-step explanation:
Given -
average annual expenditure on food and drink for all families is $5700
Mean [tex](\nu)[/tex] = 5700
standard deviation [tex](\sigma )[/tex] = 1500
Let X be the no of families spend annually on food and drink
percentage of families spend more than $4000 annually on food and drink =
[tex]P(X > 4000)[/tex] = [tex]P(\frac{X - \nu }{\sigma }> \frac{ 4000 - 5700}{1500})[/tex]
= [tex]P(Z > - 1.13)[/tex] Using [tex](Z = \frac{X - \nu }{\sigma })[/tex]
= 1 - [tex]P(Z <- 1.13)[/tex]
= 1 - .1292
= .8708
= 87.08%
