Answer:
[tex]h = 6.210\times 10^{-4}\,\frac{cal}{cm^{2}\cdot s \cdot K}[/tex]
Explanation:
The value of the heat transfer coefficient at needed units is:
[tex]h = \left(26\,\frac{J}{s\cdot m^{2}\cdot ^{\textdegree}C}\right)\cdot (\frac{1\,cal}{4.187\,J} )\cdot (\frac{1\,m^{2}}{10000\,cm^{2}} )\cdot (\frac{1\,^{\textdegree}C}{1\,K} )[/tex]
[tex]h = 6.210\times 10^{-4}\,\frac{cal}{cm^{2}\cdot s \cdot K}[/tex]
Answer:
The answer is [tex]0.000227\frac{cal}{cm^{2} sK}[/tex]
Explanation:
The unit conversion of Watts in to calories is equal to:
1 W = 0.24 cal/s
[tex]1\frac{W}{m^{2}C } *\frac{0.24\frac{cal}{s} }{1W} *\frac{1m^{2} }{100^{2}cm^{2} } *\frac{1C}{(1+273)K} =8.759x10^{-6} \frac{cal}{cm^{2} sK}[/tex]
[tex]26\frac{W}{m^{2}C } * \frac{8.759x10^{-6} \frac{cal}{cm^{2}sK } }{1\frac{W}{m^{2}C } } =0.000227\frac{cal}{cm^{2} sK}[/tex]
