contestada

A rocket in the shape of acone is attached to a cylinder with the same base radius the cone has aslant height of 15m the cylinder has abase diameter of 12m and a height of 42m find the total surface area of the rocket

Respuesta :

thaovtp1407

Answer:

the total surface area of the rocket: 1978.2  [tex]m^{2}[/tex]  

Step-by-step explanation:

Given that :

  • A rocket in the shape of a cone
  • The aslant height: 15m
  • The base diameter: 12m <=.> Radius: 6m
  • The height: 42

So the surface area of a a cone with about the base area because it is attached to a cylinder:

= π*r*l = 3.14*6*15 = 282.6 [tex]m^{2}[/tex]

The area of the cylinder is: 2*π*r*h+pi*[tex]r^{2}[/tex] (without the top part of it)

= 2*3.14*6*42 + 3.14*[tex]6^{2}[/tex]

= 1695.6 [tex]m^{2}[/tex]  

At the end, the total surface area of the rocket:

1695.6 [tex]m^{2}[/tex]  + 282.6 [tex]m^{2}[/tex] = 1978.2  [tex]m^{2}[/tex]  

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