Answer:
Current in the capacitor will be equal to 0.01 A
Explanation:
Capacitance of the capacitor [tex]C=20nF=20\times 10^{-9}F[/tex]
Capacitor voltage is change to 5 volt
So change in capacitor voltage [tex]dV=5volt[/tex]
Time taken to change in capacitor voltage [tex]dt=10\mu sec=10^{-5}sec[/tex]
Current in the capacitor is equal to
[tex]i=C\frac{dV}{dt}=20\times 10^{-9}\times \frac{5}{10^{-5}}=0.01A[/tex]
So current in the capacitor will be equal to 0.01 A
