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olatunbosunadeoke

Answer: 12Ω

Explanation:

Since there are resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2 + R3

Given that,

R1 = 3Ω

R2 = 4Ω

R3 = 5Ω

Rtotal = 3Ω + 4Ω + 5Ω

Rtotal = 12Ω (The unit of resistance is ohms, and ohms symbol is Ω)

Thus, the total resistance of the series circuit is 12Ω

gia567
Answer:12
You just need to add the resistances in a series circuit so 3+4+5=12

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