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The volume noted in the figure(9.583 L) contains nitrogen gas under a pressure of 4.97atm at 19.71°C. Calculate the number of moles of nitrogen in the tank. Round to the nearest hundredths


CAN OF NITROGEN- 9.583

Respuesta :

Answer:

The number of moles of nitrogen in the tank are 1,98.

Explanation:

We apply the ideal gas law, convert the temperature unit in Celsius to degrees Kelvin, solve for n (number of moles). The gas constant R is used with a value of 0.082 l atm / K mol:

0°C= 273 K ---> 19, 71°C= 273 + 19,71= 292, 71K

PV= nRT ---> n=PV/RT

n= 4,97 atm x 9,583 L/ 0.082 l atm / K mol x 292, 71K= 1, 98 mol