Answer:
v_f = 0.87 m/s
Explanation:
We are given;
F_avg = -17700 N (negative because it's backward)
m = 117 kg
Δt = 5.50 × 10^(−2) s
v_i = 7.45 m/s
Now, formula for impulse is given by;
I = F•Δt = - 17700 x 5.50 × 10^(−2) = - 973.5 kg.m/s
From impulse momentum theory, we know that;
Change in momentum of particle is equal to impulse.
Thus,
Δp = I = m•v_f - m•v_i
Thus,
-973.5= 117(v_f - 7.45)
Thus,
-973.5/117 = (v_f - 7.45)
-8.3205 + 7.45 = v_f
v_f = - 0.87 m/s
We'll take absolute value as;
v_f = 0.87 m/s
The final velocity, right after a 117 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padded goalpost when it experiences a backward force of 17700 N for 5.50×10−2 s is 1.95 m/s
Applying the formula of impulse,
Ft = m(v-u)................ Equation 1
Where F = force, t = time, m = mass, v = final velocity, u = initial velocity.
From the question,
GIven: F = -17700 N ( negative because it's backward force), t = 5.5×10⁻² s, m = 117 kg, u = 7.45 m/s,
Substitute these values into equation 1
-17700(0.055) = 177(v-7.45)
v-7.45 = -(17700×0.055)/177
v-7.45 = -5.5
v = 7.45-5.5
v = 1.95 m/s.
Hence, the final velocity of the rugby player is 1.95 m/s
Learn more about impulse of a force here: https://brainly.com/question/18326789
