Answer:
The magnitude of magnetic field is 1.19 T and its direction magnetic is in negative x direction.
Explanation:
Given that,
Speed of a proton, [tex]v=8.9\times 10^5\ m/s[/tex] (due +x direction)
When it moves in the positive y direction it experiences a force of, [tex]F=1.7\times 10^{-13}\ N[/tex] (due positive z direction)
We need to find the magnitude and direction of the magnetic field. The magnetic force is given by :
[tex]F=q(v\times B)\\\\B=\dfrac{F}{qv}\\\\B=\dfrac{1.7\times 10^{-13}}{1.6\times 10^{-19}\times 8.9\times 10^5}\\\\B=1.19\ T[/tex]
For direction :
[tex]F=q(v\times B)\\\\k=(+q)(j\times B)\\\\B=-i[/tex]
So, the magnitude of magnetic field is 1.19 T and its direction magnetic is in negative x direction.
