Answer: -30 m/s²
Explanation:
Given that,
Initial velocity at C (Vi) = 40 m/s
Final velocity at D Vf = 10 m/s
acceleration A = ?
Time taken T = Time at the end of segment C - Time at the start of segment C
(6s - 5s) = 1s
Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (Vf - Vi)/T
A = (10 m/s - 40 m/s) / 1s
A = -30 m/s / 1s
A = -30 m/s² (negative acceleration means the car slowed down at segment C)
Thus, the acceleration of the car at segment C is -30 m/s²
