Answer:
a. OT
b. 9.9*10^{-7}T
c. 4.6*10^{-7}T
Explanation:
The strength of a magnetic field generated by a current in a wire is
[tex]B=\frac{\mu_0I}{2\pi r}[/tex]
where mu0 is the magnetic permeability, I is the current and r is the distance in which we want to know the magnitude of B.
a. midway between the wires
r1=0.25m
r2=0.25cm
[tex]B=B_1-B_2=\frac{\mu_0I}{2\pi}(\frac{1}{r_1}-\frac{1}{r_2})=0T[/tex]
b. at a point in the plane of the wires but 3.00 m from the nearer of the two
r1=3.5m
r2=3m
in this case we have
[tex]B=B_1+B_2=\frac{\mu_0I}{2\pi}(\frac{1}{r_1}+\frac{1}{r_2})=9.9*10^{-7}T[/tex]
c. at a point between and above the two wires, 1.01 m from each one
- between the wires, as in the point a B=0T
- above each wire:
r1=1.01m
[tex]r_2=\sqrt{(1.01m)^2+(0.5m)^2}=1.43m[/tex]
[tex]B=B_1+B_2=4.6*10^{-7}T[/tex]
HOPE THIS HELPS!!
