Answer:
Step-by-step explanation:
This is your position equation:
[tex]s(t)=-4.9t^2+18t+10[/tex]
There's a whole lot of information in that equation, but what we are concerned about right now is the height of the ball after t = 3 seconds. If this is the position of the ball at any time t, we will sub in 3 for t to find out where the ball is at 3 seconds.
[tex]s(3)=-4.9(3^2)+18(3)+10[/tex]
which simplifies to
s(3) = -44.1 + 54 + 10 which is
s(3) = 19.9 meters
That's how high the ball is in the air at 3 seconds.
