Answer:
[tex](x+5)^{2} +(y+4.7)^{2} = 274[/tex]
Step-by-step explanation:
Put the xs together
[tex]x^{2} +26x + y^{2} -22y+274=0[/tex]
move the 274 to the other side, and that will be the [tex]r^{2}[/tex]
[tex]x^{2} +26x + y^{2} -22y=274[/tex]
you need [tex]x^{2}[/tex] and [tex]y^{2}[/tex]
so square root 26 is 5.09, so about 5 when rounded
[tex](x+5)^{2}[/tex]
and square root 22 is 4.69, so about 4.7 when rounded
[tex](y+4.7)^{2}[/tex]
so [tex]x^{2} +26x + y^{2} -22y+274=0[/tex]
becomes [tex](x+5)^{2} +(y+4.7)^{2} = 274[/tex]
