Explanation:
A worker picks up the bag of gravel. We need to find the speed of the bucket after it has descended 2.30 m from rest. It is case of conservation of energy. So,
[tex]\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh}[/tex]
h = 2.3 m
[tex]v=\sqrt{2\times 9.8\times 2.3} \\\\v=6.71\ m/s[/tex]
So, the speed of the bucket after it has descended 2.30 m from rest is 6.71 m/s.