An ideal spring with a force constant (spring constant) of 15 N/m is initially compressed by 3.0 cm from its uncompressed position. How much work is required to compress the spring an additional 4.0 cm?

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aristeus aristeus · Answer 1 · 2020-04-09T04:51:14+02:00

Answer:

Work done to stretch the spring additional 4 cm is 0.09 J

Explanation:

We have given spring constant of the sprig k = 15 N/m

We have to find the work require to stretch the spring additional 4 cm

Initially spring is compressed to 3 cm that is ; x = 3 cm = 0.03 m

So initial energy [tex]=\frac{1}{2}Kx^2=\frac{1}{2}\times 15\times 0.03^2=0.027J[/tex]

Now spring is compressed to additional 4 cm

So final energy [tex]=\frac{1}{2}Kx^2=\frac{1}{2}\times 15\times 0.07^2=0.036J[/tex]

So work done to compress additional 4 cm is 0.036 - 0.027 = 0.009 J