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A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do

Respuesta :

Answer:

Work done is equal to 125.44 J

Explanation:

We have given mass of the student m = 80 kg

Distance moved d = 4 m

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Coefficient of kinetic friction [tex]\mu =0.4[/tex]

So normal force exerted by student [tex]F=\mu mg=0.4\times 80\times 9.8=313.6N[/tex]

We know that work done is equal to multiplication of force and distance

So work done [tex]W=Fd=313.6\times 0.4=125.44J[/tex]

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