Answer:
The temperature at which the glass vessel shatter is = 341.33°c
Explanation:
Initial temperature [tex]T_{1}[/tex] = 18 °c = 291 K
Initial Pressure [tex]P_{1}[/tex] = 0.9 atm
Final pressure [tex]P_2[/tex] = 1.9 atm
From ideal gas equation
P V = m R T
Here volume & mass & gas constant is constant so Pressure is directly proportional to the temperature.
[tex]\frac{P_{2} }{P_{1} } = \frac{T_2}{T_1}[/tex]
[tex]\frac{1.9}{0.9} = \frac{T_2}{291}[/tex]
[tex]T_2[/tex] = 613.33 K = 341.33°c
Therefore the temperature at which the glass vessel shatter is = 341.33°c