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Jeff, a snowboarder who weighs 1000 N, is practicing on a trampoline for an upcoming competition. As Jeff bounces straight up off the trampoline, his speed is 6.26 m/sec. When he reaches the top of his bounce, his potential energy is approximately:

Respuesta :

Answer:

Potential energy [tex]P_E = 2000 J[/tex]

Explanation:

Given data

Weight of the person = 1000 N

Mass of the person = [tex]\frac{1000}{9.81} = 102 kg[/tex]

Speed = 6.26 [tex]\frac{m}{s}[/tex]

Kinetic energy is given by

[tex]E_K = \frac{1}{2} m v^{2}[/tex]

Put the values in above formula we get

[tex]E_K = \frac{1}{2}(102) 6.26^{2}[/tex]

[tex]E_K = 2000 J[/tex]

When the person reach top point then at this point the velocity is zero & kinetic energy at top point is equals to the potential energy.

Therefore potential energy

[tex]P_E = 2000 J[/tex]

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