Respuesta :
Answer:
0.25
Explanation:
The rate law for the reaction:
2A(g) + 2B(g) ⟶ 2A(g) + 2B(g)
has been determined to be rate = k[2A]2[2B]. What are the orders with respect to each reactant, and what is the overall order of the reaction?
Answer:
order in 2A= 0.15; order in 2B = 0.10; overall order = 0.25
Answer:
The rate constant k is ;
K = 2572 L^4/mol^-4•s
Explanation:
In this question, we are asked to calculate the rate constant given the chemical equation above.
First, we need to write a complete expression for the rate law. The reaction is a second order type.
We write the rate law as follows;
Rate = k * [A]^2 * [B]^3
Where k is the rate constant and the square brackets indicate the concentrations of both A and B. Let’s input the values :;
0.1 = k * (0.15)^2 * (0.12)^3
0.1 = k * 0.0225 * 0.001728
0.1 = k * 0.00003888
K = 0.1/0.00003888
K = 2572 L^4/mol^-4•s
