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Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
equation and information in Appendix Table B–5 and Table B–14. Write out the solution
according to Hess’s law.

Respuesta :

5027476

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

The study of chemicals and bonds is called chemistry.

The correct answer is -137.4

The equation used in the question is:-

[tex]4C(s) + 5H_2(g) = C_4H_{10[/tex]

What is hess's law?

  • Hess' law states that the change of enthalpy in a chemical reaction is the same regardless of whether the reaction takes place in one step or several steps, provided the initial and final states of the reactions and products are the same.

The enthalpy is given as follows:-

[tex]C(s) + O_2(g) =O_2(g) =393.5 \\H_2(g) + \frac{1}{2}O2(g) =H20(l) = 285.8 2\\CO_2(g) + 3H_2O(l) = \frac{13}{2} O_2 (g) + C_4H_10 = 2877.1 reverse[/tex]

To get the target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

[tex]-1586+(-1429) +2877.6\\=-137.4[/tex]

Hence, the correct answer is -137.4.

For more information about the Hess law, refer to the link:-

https://brainly.com/question/22953190

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