Answer:
[tex]15\text{miles}[/tex]
Step-by-step explanation:
GIVEN: A boy cyclist and a girl cyclist are [tex]10[/tex] miles apart and pedaling toward each other. The boy's rate is [tex]4[/tex] miles per hour, and the girl's rate is 6 miles per hour. There is also a friendly fly zooming continuously back and forth from one bike to the other. If the fly's rate is [tex]15[/tex] per hour.
TO FIND: By the time the cyclists reach each other, how far does the fly fly?
SOLUTION:
Boy's speed of riding cycle [tex]=4\text{mph}[/tex]
Girl's speed of riding cycle [tex]=6\text{mph}[/tex]
Total distance between both [tex]=10\text{miles}[/tex]
as both are heading towards each other
relative speed of boy and girls [tex]=\text{speed of girl cyclist}+\text{speed of boy cyclist}[/tex]
[tex]=10\text{mph}[/tex]
Time taken by both cyclist to reach each other [tex]=\frac{\text{total distance between both}}{\text{relative speed of both}}[/tex]
[tex]=\frac{10}{10}\text{hours}[/tex]
Speed of fly [tex]=15\text{mph}[/tex]
distance traveled by fly by the time cyclists reach each other [tex]=\text{speed of fly}\times\text{time taken by cyclists to reach each other}[/tex]
[tex]=15\times1\text{miles}[/tex]
[tex]=15\text{miles}[/tex]
Hence the fly [tex]15\text{miles}[/tex] far by the time both cyclists reach each other.