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The composition of an ideal gas mixture, by volume, is 30% nitrogen (N2), 30% oxygen (O2), and 40% hydrogen (H2). The mass fraction of oxygen, in percentage, is (round to nearest integer; for example if the answer is 14.6%, write 15; if the answer is 14.49% write 14; do not include the % symbol in your answer):

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Edufirst

Answer:

  • 34%

Explanation:

Since the gas mixture is ideal, the composition by volume is equal to the composition by moles.

Thus, the mole composition is:

  • N₂: 30%
  • O₂: 30%
  • H₂: 40%

Use a basis of 100 moles and find the mass of each gas, using its corresponding molar masss:

  • N₂: 30 moles × 28g/mol = 840 g
  • O₂: 30 moles × 16g/mol = 480 g
  • H₂: 40 moles × 2g/mol = 80 g

Total mass = 840g + 480g + 80g = 1,400g

Then, the mass fraction of oxgygen is the mass of oxygen divided by the total mass of the gas mixture:

  • 480g/1,400g = 0.3429

Which in percentage is 34.29%.

Rounded to the nearest integer that is 34% ← answer

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