The combustion of propane gas is used to fuel barbeque grills. If 4.65 moles of propane, C3H8, are burned in a grilling session, how many moles of carbon dioxide gas are formed? C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)

Combustion reaction: The reacion in which hydrocarbon is burnt in the presence of oxygen gas and it releases heat and this reaction exothermic because heat of cumbustion is negative.

eg. burning of methane

By using unitry method,

From the above balanced reaction it is clearly that,

from 1 mole of propane 3 moles of carbon dioxide is formed

there fore,

from 4.65 mole of propane [tex]3 \times 4.65[/tex] moles of carbon dioxide will form

moles of carbon dioxide=13.95mol

Oseni Oseni · Answer 2 · 2021-11-23T10:57:22+01:00

If 4.65 moles of propane are burned in a grilling session, the moles of carbon dioxide that would be formed will be 13.95 moles

Propane burns in air according to the following equation:

[tex]C_3H_8(g) + 5 O_2(g) ---> 3 CO_2(g) + 4 H_2O(l)[/tex]

The mole ratio of propane burned to the carbon dioxide released is 1:3. In other words, for every 1 mole of propane burned, 3 moles of carbon dioxide are produced.

Now, if 4.65 moles of propane is burned, the amount of carbon dioxide that will be produced can be calculated, such that:

Amount of CO2 produced = 3 x 4.65

= 13.95 moles

More on mole ratio can be found here: https://brainly.com/question/15288923