The mass of CO₂ present is 238.52g
Explanation:
Given:
Volume, V = 81.3 L
Pressure, P = 204 kPa = 204000 Pa
Temperature, T = 95°C
T = 95 + 273 K
T = 368 K
Mass of CO₂, x = ?
Molecular weight of CO₂ = 44 g/mol
According to gas law:
PV = nRT
where,
n = number of moles
n = given mass/ molecular mass
R = gas constant
R = 8.314 X 10³ L Pa K⁻¹ mol⁻¹
Substituting the value:
[tex]204000 X 81.3 = \frac{x}{44} X 8.314 X 10^3 X 368\\ \\x = \frac{44 X 204 X 81.3}{8.314 X 368} \\\\x = 238.52 g[/tex]
Therefore, the mass of CO₂ present is 238.52g
