For a copper-silver alloy of composition 25 wt% Ag-75 wt% Cu and at 775C (1425F) do the following: (a) Determine the mass fractions of α and β phases. (b) Determine the mass fractions of primary α and eutectic microconstituents. (c) Determine the mass fraction of eutectic α.

Respuesta :

Answer:

a)

mass fraction of α = 0.796

mass fraction of β = 0.204

b)

mass fraction of primary α (Wα) = 0.734

mass fraction of  eutectic micro-constituents (We) = 0.266

c)

α in eutectic mixture = 0.062

Explanation:

Assumptions:

(i) the  system is in thermal equilibrium with its surroundings

(ii) There are no impurities or other alloying elements present

(a) Determine the mass fractions of α and β phases

From the Cu - Ag phase diagram, Cα = 8.0 wt% Ag, Cβ = 91.2 wt% Ag, and C0 = 25 wt% Ag .Using the lever-rule:

Total mass fraction of α = (Cβ - C0) / (Cβ - Cα) = (91.2 - 25) / (91.2 - 8) = 0.796

Total mass fraction of β = (C0 - Cα) / (Cβ - Cα) = (25 - 8) / (91.2 - 8) = 0.204

(b) Determine the mass fractions of primary α and eutectic microconstituents

Ceutetic = 71.9 wt.%Ag

mass fraction of primary α (Wα) = (Ceutetic - C0) / (Ceutetic - Cα) = (71.9 - 25) / (71.9 - 8) = 0.734

mass fraction of  eutectic micro-constituents (We) = (C0 - Cα) / (Ceutetic - Cα) = (25 - 8) / (71.9 - 8) = 0.266

(c) Determine the mass fraction of eutectic α.

From the eutetic reaction, L  ↔    α + β

Total α = Primary α + α in eutectic mixture

Therefore: α in eutectic mixture = Total α - Primary α = 0.796 - 0.734 = 0.062

A) The mass fractions of α and β phases are respectively; Wα = 0.8 and Wβ = 0.20

B) The mass fractions of primary α and eutectic microconstituents are respectively; Wα = 0.73 and W_e = 0.27

C) The mass fraction of eutectic α is; Wα = 0.07

What is the mass fraction?

(a) We are trying to find the mass fractions of α and β phases.

From the Cu - Ag phase diagram, we have;

Cα = 8.0 wt% Ag

Cβ = 91.2 wt% Ag

C₀ = 25 wt% Ag

Using the lever-rule, we have;

Total mass fraction of α is;

Wα = (Cβ - C₀)/(Cβ - Cα)

Wα = (91.2 - 25)/(91.2 - 8)

Wα = 0.8

Total mass fraction of β is;  

Wβ = (C₀ - Cα)/(Cβ - Cα)

Wβ = (25 - 8)/(91.2 - 8)

Wβ = 0.20

(b) We want to find the mass fractions of primary α and eutectic microconstituents. We have;

C_eutetic = 71.9 wt.%Ag

Mass fraction of primary α is;

Wα = (C_eutetic - C₀) /(C_eutetic - Cα)

Wα = (71.9 - 25)/(71.9 - 8)

Wα = 0.73

Mass fraction of  eutectic micro-constituents is;

W_e = (C₀ - Cα)/(C_eutetic - Cα)

W_e = (25 - 8)/(71.9 - 8)

W_e = 0.27

(c) Determine the mass fraction of eutectic α.

From the eutetic reaction;

Total α = Primary α + α in eutectic mixture

Thus:

mass fraction of eutectic α = Total α - Primary α

mass fraction of eutectic α = 0.8 - 0.73 = 0.07

Read more about Mass fractions at; https://brainly.com/question/7578928